For example: SELECT COUNT(*) FROM (SELECT 'Dummy' AS [Dummy] WHERE 1 = 0) DummyTable. Will return one record with the value '0', where as: SELECT COUNT(*) FROM (SELECT 'Dummy' AS [Dummy] WHERE 1 = 0) DummyTable GROUP BY [Dummy].
Shouldn't select count(*) take more time to execute since it makes more operations? To output all the results from select * I need 4 minutes (not 32 seconds, as indicated by server log). I understand that the client has to output a lot of data and it will be slow, but what about the server's log?
Синтаксис функции COUNT: SELECT COUNT(expression) FROM table WHERE predicates; Функция COUNT принимает один из нескольких параметров
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...union select unhex(hex(version())) -- 'x'='x labor op99999' union select unhex(hex(version
AND(SELECT COUNT(*) FROM (SELECT 1 UNION SELECT null UNION SELECT !1)x GROUP BY CONCAT((SELECT column_name FROM information_schema.columns LIMIT 1),FLOOR
mysql> SELECT * FROM worker WHERE name LIKE '%ex'
(M): SELECT CONCAT(login, password) FROM members. 7. Строки без кавычек Есть несколько
InnoDB handles SELECT COUNT(*) and SELECT COUNT(1) operations in the same way. There is no performance difference.
SELECT CONCAT("SQL ", "Tutorial ", "is ", "fun!") AS ConcatenatedString; Try it Yourself ». Definition and Usage. The CONCAT() function adds two or more expressions together.