SELECT COUNT(*)(SELECT DISTINCT a.my_id, a.last_name, a.first_name, b.temp_val. FROM Table_A a INNER JOIN Table_B b on a.a_id = b.a_id).
SELECT id, SUM(CASE WHEN status = 3 THEN 1 ELSE 0 END) as status_3_count FROM yourtable GROUP BY id. or just use a WHERE status = 3
I want my query to get ID, Value; meanwhile the returned set should be in the order of frequency count of each ID. I tried the query below but don't know how to get the ID and Value column at the same time
select count(*) is mostly equivalent to select count(id) where id is the primary key.` I have always favored select count(1); I even always use if exists
select * from (select w.nm_city,i.id_city from installation i join city w on i.id_city=w.id_city group by i.id_city) WIL, (select count(*) as suc from installation where sts=1) SUC, (select count(*) as fail from installation
Shouldn't select count(*) take more time to execute since it makes more operations? To output all the results from select * I need 4 minutes (not 32 seconds, as indicated by server log). I understand that the client has to output a lot of data and it will be slow, but what about the server's log?
...id=84' AND (select 1 from(select count(*), concat(0x3a,0x3a,(select table_name from information_schema.tables where table_schema=database() limit 54,1)
SELECT COUNT(*) AS num_rows FROM (SELECT * FROM sysobjects WHERE TYPE = 'u' AND name = 'system_configuration'). I send this query via PHP and the sqlsrv extension to a SQL Sever 2005.
Для этого в SQL существует оператор SELECT. Синтаксис его использования следующий
mysql> SELECT * FROM worker WHERE name LIKE 'And%'