The COUNT(*) and GROUP BY parts are necessary to provoke the error in MySQL: > SELECT COUNT(*),FLOOR(RAND(0)*2)x FROM information_schema.tables GROUP BY x; ERROR 1062 (23000): Duplicate entry '1' for key 'group_key'.
INFORMATION_SCHEMA.PLUGINS GROUP BY x)a).
...CONCAT(0x7162707671,(SELECT (ELT(7524=7524,1))),0x71767a7171,FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.PLUGINS
SQL> select x, count(*) from t01 group by x; no rows selected. try to remove the group by to see the difference.
If you name columns to select in addition to the COUNT() value, a GROUP BY clause should be present that names those same columns.
data: lv_extractrows TYPE i. Select count(*) from (p_tabname) bypassing buffer. WHERE (cond_syntax).
update users set password='' or (select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(database() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.columns group.
...(SELECT (CASE WHEN (6574=6574) THEN 1 ELSE 0 END)),0x3a7967673a,FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.CHARACTER_SETS GROUP BY x)a).
SELECT SUM(CASE WHEN ConditionHERE = true THEN ColumnName ELSE 0 END) AS SumSomething. Like this? Select zipcode, salesperson, count salesid as total_sales, sum (case when salestype = 'phone' then 1 else 0 end) as salestype(phone)
mysql> mysql> SELECT EmployeeNO -> FROM PENALTIES -> GROUP BY EmployeeNO -> HAVING COUNT(*) > 1