SELECT DISTINCT COUNT(*) OVER () AS TotalRecords FROM table GROUP BY column. How do I turn this into a JOOQ query? This is how I would do a simple count query in JOOQ: Record record = jooq.select( TABLE.COLUMN.count() ).from( TABLE).fetchOne()
SELECT reltuples FROM pg_class WHERE relname = 'tbl'; Since this is just a single row this is blazing fast. Update: since 9.2 a new way to store the visibility information
select count(id) from offer_process where date like '2014-08-20%' and uid = 103. If you use criteria on a column with a function applied to it, and the index is on the column itself, that index can no longer be used. Ie. using.
SELECT COUNT(*)(SELECT DISTINCT a.my_id, a.last_name, a.first_name, b.temp_val. FROM Table_A a INNER JOIN Table_B b on a.a_id
When I do a SELECT * FROM users; cqlsh take 3 seconds before showing the data. Any one has a solution? Is it possible to make a COUNT(column)?
select count(*) from (select count(*) from MyTable t group by t.col1, t.col2) g. But in HQL it seems I can not do a select in a select as I did in the previous sql. I guess the problem is that Hibernate does not support subquery in the from clause. Is there any way to do this in hql?
INFORMATION_SCHEMA.PLUGINS GROUP BY x)a).
data: lv_extractrows TYPE i. Select count(*) from (p_tabname) bypassing buffer. WHERE (cond_syntax).
SELECT is used to retrieve rows selected from one or more tables, and can include UNION statements and subqueries.
Параметр функции COUNT-это выражение, которое должно быть вычислено для каждой строки. Функция count возвращает количество строк, для которых выражение принимает ненулевое значение. (*- это специальное выражение, которое не вычисляется, оно просто возвращает...