Union select null, null, null, null, null, null, null from information_schema.tables. for a small database containing three tables. this instruction is used in sql injection I tried it and it worked but I didn't really know how it works can somebody help me...
Select count(distinct col1) + count(distinct case when col1 is null then 1 end) from YourTable.
Синтаксис функции COUNT: SELECT COUNT(expression) FROM table WHERE predicates; Функция COUNT принимает один из нескольких параметров
Shouldn't select count(*) take more time to execute since it makes more operations? To output all the results from select * I need 4 minutes (not 32 seconds, as indicated by server log). I understand that the client has to output a lot of data and it will be slow, but what about the server's log?
1 1 1 NULL NULL NULL 2 2 NULL 1 3 1. Then. SELECT COUNT(*), COUNT(Field1), COUNT(Field2), COUNT(DISTINCT Field3) FROM Table1. Output Is: COUNT(*) = 4; -- count all rows, even null/duplicates --.
Given the query SELECT permission FROM Users WHERE id = {INJECTION POINT}; -1 union select 1 into @
Синтаксис: 0xHEX_ЧИСЛО (SM): SELECT CHAR(0x66) (S) SELECT 0x5045 (это не число, а
Если вы используете базу данных MySQL, это очень важно, чтобы вы работали комфортно с командной строкой MySQL. На этом уроке мы расскажем, как использовать команду SELECT в MySQL с несколькими...
Сюда входят значения NULL и повторяющиеся