you should change char* to char, right now numberstring is an array of pointers – josefx Jun 1 '12 at 9:10.
I know that for cannot convert char to char * you just use the & in front of the char, but I cannot figure out what to do in this case.
Handling all three char types (signed, unsigned, and char) is more delicate than it first appears.
char x = (char)wc; but because it's an integral type, there's absolutely no reason to do this.
A char in C is already a number (the character's ASCII code), no conversion required.
The string contains only chars in the '0'..'9' range. The character encoding used is ASCII.
Функция установки курсора: void LCD_Goto(unsigned char x, unsigned char y) { LCD_X = x; LCD_Y = y; sendCommand(0xB0 + y); sendCommand(x
Declare a string const char * xyz = "this is a string" and it will use up RAM.
Есть, например, char x - это область в памяти размером один байт, у которой есть имя x. Область в памяти имеет свой адрес в памяти.
компилятор ругается на char. и ктому же мне нужно постоянно ее изменять, добавлять путь и удалять символы "*.*"