SELECT COUNT(*)(SELECT DISTINCT a.my_id, a.last_name, a.first_name, b.temp_val. FROM Table_A a INNER JOIN Table_B b on a.a_id
Чёрный властелин 19 августа 2014 в 15:02. Mysql: полезный трюк с count() и count(distinct).
Задачи по SQL запросам. Задание: 1 (Serge I: 2002-09-30). Найдите номер модели, скорость и размер жесткого диска для всех ПК стоимостью менее 500 дол. Вывести: model, speed и hd. SELECT model, speed, hd FROM PC WHERE price < 500. Задание: 2 (Serge I: 2002-09-21).
SELECT name, count(*) cnt FROM names WHERE g_number='123' ORDER BY rand(). But result is always the same.
select 1,2 union select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x; ERROR 1062 (23000): Duplicate entry '5.0.841' for key 1.
In this video you will learn how measure distance using VL53L0X 6 pin Laser module. You will see (click on time to watch directly) -Hardware explained at 00...
When I execute SELECT COUNT(*) FROM TABLE, the output is "1," but the input file has multiple JSON records. I used org.openx.data.jsonserde.JsonSerDe to create the table. Why is the query returning the wrong value?
SQL COUNT() function Syntax SELECT COUNT (column_name) FROM table_name.
[*] Modaco_GR9_V&M&S_edition v2.0ВЫБОР ПОЛЬЗОВАТЕЛЕЙ от пользователей Vedroid(sergeysadoha), M1sterGrace и sam_top7.