select town, count(town) from user group by town. You can use most aggregate functions when
You're missing a FROM and you need to give the subquery an alias. SELECT COUNT(*) FROM (. SELECT DISTINCT a.my_id, a.last_name, a.first_name, b.temp_val FROM dbo.Table_A AS a INNER JOIN dbo.Table_B AS b ON a.a_id = b.a_id ) AS subquery;
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Что называется total shared groups. В итоге всё поместилось в один компактный запрос без
SELECT product, count(product_sale.product_id) as no FROM `product` , product_sale where product_sale.product_id=product.product_id group by
mysql> SELECT COUNT(DISTINCT results) FROM student; In MySQL, you can obtain the number of distinct expression combinations that do not contain NULL by giving a list of expressions. In standard SQL, you would have to do a concatenation of all expressions inside COUNT(DISTINCT ...).
Select2 is a jQuery based replacement for select boxes. It supports searching, remote data sets, and pagination (infinite scrolling) of results.
SELECT COUNT(*) FROM count_demos; This example uses the COUNT(*) function with a WHERE clause to specify a condition to count only rows whose value in