@kevin001 If you want to convert the char to int and a character '1' provides a ascii number that's not 1, you need to remove the offset '0' to realign it to count from 0-9.
A char in C is already a number (the character's ASCII code), no conversion required.
you should change char* to char, right now numberstring is an array of pointers – josefx Jun 1 '12 at 9:10.
define char variable for the app name. char ichar = "konqueror "; //define a char
Why don't I have to convert int to char with getchar() when reading into a buffer in C?
Then your char could be said to be 'converted'.
Keep these four rules in mind when writing your SAS statements: PUT() always creates character variables.
CHARTOROWID. Строку в значение типа ROWID. CONVERT. Строку из одного набора символов в другой.
static tz_rule tz_rules; 63. 64. 65. static void compute_change (tz_rule *rule, int year) __THROW