You can convert a char type simply by assigning to an int.
int search_book(){ int select_search; char dumpchar[30]
int length = 10; char len = length + '0'; printf("%c", len); This gave me : for 58 on the ascii chart not 10 that I wanted.
I understand that I cannot convert an int* into a char* but must copy the int* into a char* array using sprintf. My issue is that I believe I am using sprintf correctly but I am getting this warning: warning: passing argument 1 of ‘sprintf’ from incompatible pointer type. Here is a condensed and simplified...
int a = 65; char c = (char) a; Note that since characters are smaller in size than integer, this casting may cause a loss of data.
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Перевожу char в int, но на выходе неверное число, вот упрощений вариант
Here, we used '0' because chars are actually represented by ASCII values. '0' is a char and represented by the value of 48. We typed (a + '0') and in order to add these up, Java converted '0' to its ASCII value which is 48 and a is 1 so the sum is 49. Then what we did is
Если нужно перевести число в строку на си (char *), то лучше всего использовать стандартную функцию