The expression UChar( c ) converts to unsigned char in order to get rid of negative values, which, except for EOF, are not supported by the C functions. Then the result of that expression is used as actual argument for an int formal argument. Where you get automatic promotion to int.
I know that for cannot convert char to char * you just use the & in front of the char, but I cannot figure out what to do in this case.
Translator, Binary. This application encodes and decodes ASCII and ANSI text. Only codepoints < 128 are ASCII. This is provided for educational and entertainment use only. *** Thank you for staying tuned, we are end-to-end encrypted for your protection! ***
int length = 10; char len = length + '0'; printf("%c", len); This gave me : for 58 on the ascii chart not 10 that I wanted.
int search_book(){ int select_search; char dumpchar[30]
Сделать преобразование unsigned char в char, а затем типу int Здраствуйте, есть вопрос: Число представлено двумя полями: типа long для
...С const char* numbercsz(signed long long number) { char* result = new char[21], *index = result