char strTMP[1]; char testint2[] = "BLA BLA BLA "; strTMP[0] = c[i]; // returns a
Casting int to char involves losing data and the compiler will probably warn you.
Now I want convert p(char *) to pwcsName(WCHAR *). Can anybody suggest me how do this? Is it done using "mbtowc" function or MultiByteToWideChar...
void readLoraChanel() { if (!LORA_ENABLED) return; int packetSize = LoRa.parsePacket(); if (packetSize) { Serial.print(F("Received packet '")); while (LoRa.available()) { Serial.print((char)LoRa.read())
...int main(int argc, char **argv) ... unsigned char *wandData = (unsigned char *)malloc(fileSize)
Компилятор Visual C++ поддерживает char и wchar_t как встроенные типы данных для кодировок ANSI и UNICODE.Хотя есть более конкретное определение Юникода, но для понимания, ОС Windows использует именно 2-х байтовую кодировку для много языковой поддержки приложений.
How can I convert a wchar_t * to char *? My code is something like that but it just get the first character
I am trying to convert a char string to a wide char string. #include using namespace std; int main(int argc, char* argv) { if
tolower toupper isupper */. int main(){ char c = 'a'
Also, const char* is a pointer to an array of characters. Strings in C/C++ can be like this, and the problem then is that it has no idea of the size at runtime and it doesn't have any operations associated with it. This is why your theoretical username.endswith will never work.