I have the string str. char *str = "100.10b.100.100"; I want to count the occurrences of '.' in str, preferably a one-liner. (If possible no loops). My approach would be the standard strchr: int i = 0; char *pch=strchr(str,'.'); while (pch!=NULL) { i++; pch=strchr(pch+1
Другие символы. NUL. Null. (No character- нет данных). Используется для передачи в случае отсутствия данных.
> char array[SIZE] = {0}; Nothing wrong with this. It just assumes that the remaining SIZE-1 elements are also zero, so that's it, job done.
char* is pointer to a char. char[] is an incomplete type and indicates a character array. std::string is a string (class) from the standard (template) library.
1. Putting char into a java string for each N characters stackoverflow.com. I have a java string, which has a variable length.
Is there a way to set a char variable to 0 or null or something so that it will basically reset my control variable.
У NULL слишком важное значение в теории баз дан��ых чтобы его заменить на пустое значение.
Ken Sanchez NULL * Terri Duffy NULL * Roberto Tamburello NULL * Rob Walters NULL * Gail Erickson Ms. * (5 row(s) affected). When you convert data types that differ in decimal places, SQL Server will sometimes return a truncated result value, and at other times it will return a rounded value.