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Compare: select foo.bar from foo union select fizz.buzz from fizz against select case when foo.bar is null then fizz.buzz else foo.bar end from foo join fizz where
11223344) UNION SELECT NULL,NULL,NULL,NULL WHERE 1=2 –- No Error - Syntax is right. MS SQL Server Used.
Даже выражение NULL != NULL не будет истинным, ведь нельзя однозначно сравнить одну неизвестность с другой.
5 select 4, 'item4', null , null from dual 6 ), 7 remcom 8 -- remove leading and trailing commas 9 as (select id, 10 name, 11 rtrim(ltrim(cola, ' ... ') cola, 12 rtrim(ltrim(colb
I was trying to select orders by a date and then join any previous orders on the same user_id from previous dates, then count how many had orders, vs how many didnt. This was my failed attempt: SELECT SUM( CASE WHEN id IS NULL THEN 1 ELSE 0 END ) AS new, SUM( CASE WHEN id IS...
SELECT * FROM table_name MATCH_RECOGNIZE( PARTITION BY stock ORDER BY cdate MEASURES
, case when col_a is null and col_b is null and col_C is null and col_D is null and col_e = 0 and col_f = 1 then nvl(col_a, 0.06077) end. The following did fill the entries meeting my set conditions. Anyone knows a potential sollution?
17 b, 18 decode(a, 19 0, 20 null, 21 sum(b) over(order by rownum rows between unbounded
SESSION 2> select * from test_table; no rows selected SESSION 1> insert into test_table values (1); 1 row created. SESSION 1> commit; Commit complete.
SELECT CASE WHEN (SELECT usergroup FROM usergr WHERE usergroupnumber = (SELECT usergroupnumber FROM userlist WHERE username='Carl')) LIKE '%contractor%' THEN 1 ELSE 0 END FROM DUAL. Теперь этот подзапрос возвращает более 1 строки, потому что Carl является...