1' UNION SELECT @--+ #The used SELECT statements have a different number of columns 1' UNION SELECT @,@--+ #The used
Thank you. SELECT COUNT(*)(SELECT DISTINCT a.my_id, a.last_name, a.first_name, b.temp_val. FROM Table_A a INNER JOIN Table_B b on a.a_id = b.a_id).
SELECT in the FROM or SELECT.
SELECT id, SUM(CASE WHEN status = 3 THEN 1 ELSE 0 END) as status_3_count FROM yourtable GROUP BY id. or just use a WHERE status = 3
SELECT GenderId,Gender,Count FROM CTE GROUP BY GenderId,Gender. I want to something like what LinkedIn is doing with search(people search,job search).
EXPLAIN SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = "transactions". id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE COLUMNS ALL NULL TABLE_NAME NULL NULL...
select count(*) from ( select p.UserName, p.FirstName + ' ' + p.LastName as [FullName] ,count(b.billid) as [Count], sum(b.PercentRials) as [Sum] from Bills b inner join UserProfiles p on b.PayerUserName=p.UserName where b.Successful=1 group by...
FROM (SELECT ...) Надо найти имя таблицы из другой таблицы, а потом из этой найденной таблицы сделать выборку. Сделал я такую конструкцию: SELECT quest_p FROM (SELECT name_r FROM themes WHERE id=1); - интерпретатор говорит, что надо использовать что-то...
Синтаксис: 0xHEX_ЧИСЛО (SM): SELECT CHAR(0x66) (S) SELECT 0x5045 (это не число, а строка) (M) SELECT 0x50
SQL> select count(*) from t group by 1; no rows selected. I’ll skip the entire SQL for the materialized view refresh process (it’s long and you can always